Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 3 - Mass Relationships in Chemical Reactions - Questions & Problems - Page 107: 3.6

Answer

7.5% and 92.5%

Work Step by Step

To solve this question, you need to set up an algebra equation. Set the percentage (natural abundance) of one isotope equal to x (decimal format), and the other equal to 1-x. You will end up with something like this: $6.0151x+7.0160(1-x)=6.941$ or $6.0151(1-x)+7.0160(x)=6.941$. Then solve for x. If you used the first equation, your answer for x will be the number of Lithium-6 isotopes, and if you solved for the second equation your answer for x will be the number of Lithium-7 isotopes. Using your value for x, subtract it from one to get the other isotope's natural abundance. Afterward, make sure to round to the desired number of significant digits and to convert it to percentage form.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.