Answer
Please see the work below.
Work Step by Step
We know that
$rate=K[NH_4^+][NO_2^-]$
We plug in the known values to obtain:
$rate=3.0\times 10^-4(0.26M)(0.080M)$
$rate=6.2\times 10^{-6}\frac{M}{s}$
Chemistry 12th Edition
by Chang, Raymond; Goldsby, Kenneth
Published by
McGraw-Hill Education
ISBN 10:
0078021510
ISBN 13:
978-0-07802-151-0
Chapter 13 - Chemical Kinetics - Questions & Problems - Page 609: 13.13
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