Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 11 - Intermolecular Forces and Liquids and Solids - Questions & Problems - Page 512: 11.77

Answer

Please see the work below.

Work Step by Step

We can calculate the required heat as $\Delta H=4.18\frac{J}{gC^{\circ}}\times 74.6g\times 100C^{\circ}\times \frac{1KJ}{1000J}=31.2KJ$
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