Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 11 - Intermolecular Forces and Liquids and Solids - Questions & Problems - Page 512: 11.73

Answer

Molar heat of vaporization of water = $40.67 kJ/mol$ Hence, energy released when 1 mole of steam is converted to 1 mole of water at $100^{\circ}C = -40.67 kJ/mol$ Molar heat of fusion of water = $6.02 kJ/mol$ Hence, energy released when 1 mole of water is converted to 1 mole of ice at $0^{\circ}C = -6.02 kJ/mol$ 1 mole of steam being converted to 1 mole of water at $100^{\circ}C$ gives more heat.

Work Step by Step

Molar heat of vaporization of water = $40.67 kJ/mol$ Hence, energy released when 1 mole of steam is converted to 1 mole of water at $100^{\circ}C = -40.67 kJ/mol$ Molar heat of fusion of water = $6.02 kJ/mol$ Hence, energy released when 1 mole of water is converted to 1 mole of ice at $0^{\circ}C = -6.02 kJ/mol$ 1 mole of steam being converted to 1 mole of water at $100^{\circ}C$ gives more heat.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.