Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 1 - Chemistry: The Study of Change - Questions & Problems - Page 33: 1.74

Answer

$$7.0 \times 10^{20} \space L$$

Work Step by Step

$$1.8 \times 10^8 \space km^2 \times \Bigg(\frac{1000 \space m}{1 \space km} \Bigg)^2 = 1.8 \times 10^{14} \space m^2$$ $$V = 1.8 \times 10^{14} \space m^2 \times 3.9 \times 10^3 \space m = 7.0 \times 10^{17} \space m^3$$ $$7.0 \times 10^{17} \space m^3 \times \frac{1000 \space L}{1 \space m^3} = 7.0 \times 10^{20} \space L$$
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