Answer
$8084.4 g$
Work Step by Step
radius: 10.0 cm
density of gold: 19.3 g/cm3
Volume of sphere:
$\frac{4πr^3}{3}$
=$\frac{4000π}{3}$
Mass= Density x Volume
= $\frac{(19.3)(4000π)}{3}$
$\approx8084.365095 g$
$=8084.4 g$ (1 s.f.)
Chemistry 12th Edition
by Chang, Raymond; Goldsby, Kenneth
Published by
McGraw-Hill Education
ISBN 10:
0078021510
ISBN 13:
978-0-07802-151-0
Chapter 1 - Chemistry: The Study of Change - Questions & Problems - Page 32: 1.57
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
