Lehninger Principles of Biochemistry 6th Edition

Published by W.H. Freeman
ISBN 10: 1-42923-414-8
ISBN 13: 978-1-42923-414-6

Chapter 2 - Water - Problems: 12

Answer

a) 5.06 b) 4.28 c) 5.46 d) 4.76 e) 3.76

Work Step by Step

Henderson-Hasselbalch equation: pH = $pK_{a}$ + log([Acetate]/[Acetic acid]) $pK_{a}$ = 4.76 pH = 4.76 + log([Acetate]/[Acetic acid]) a) pH = 4.76 + log(2/1) = 4.76 +0.3 = 5.06 b) pH = 4.76 + log(1/3) = 4.76 -0.48 = 4.28 c) pH = 4.76 + log(5/1) = 4.76 +0.7 = 5.46 d) pH = 4.76 + log(1/1) = 4.76 +0 = 4.76 e) pH = 4.76 + log(1/10) = 4.76 -1 = 3.76
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