#### Answer

$\frac{27}{64}$

#### Work Step by Step

For each of the three traits in this question (flower color, seed shape, seed color), the first listed parent is homozygous dominant (since all of phenotypes in the F1 generation are the same as in the parents), and the second parent is homozygous recessive, for the same reason plus the fact that all of its phenotypic descriptions match the recessive version for each gene. That means that there will be a $\frac{3}{4}$ chance for each of the three traits to show the dominant form in the F2, and the chance for all three to be dominant is
$\frac{3}{4}$ times $\frac{3}{4}$ times $\frac{3}{4}$=$\frac{27}{64}$