Answer
$x = 3$
Work Step by Step
$a^{2} + b^{2} = c^{2}$
$(4)^{2} + x^{2} = (x+2)^{2}$
$16 + x^{2} = (x+2)(x+2)$
$16 + x^{2} = x(x+2)+2(x+2)$
$16 + x^{2} = x^{2} + 2x + 2x + 4$
$16 + x^{2} = x^{2} + 4x + 4$
$16 + x^{2} - x^{2} - 4x - 4 = 0$
$16 - 4x - 4 = 0$
$12 - 4x = 0$
$-4x = -12$
$4x = 12$
$x = \frac{12}{4}$
$x = 3$
