Answer
$\angle A=42^{\circ}$
$a=240$
$c=360$
Work Step by Step
The sum of the angles in a triangle is $180^{\circ}$.
Therefore, $\angle A=180^{\circ}-(90^{\circ}+48^{\circ})=42^{\circ}$
$\tan A=\frac{\text{opposite side to A}}{\text{adjacent side to A}}=\frac{a}{b}$
$\implies \tan 42^{\circ}=\frac{a}{270}$
$\implies a=\tan 42^{\circ}\times270=240$
$\cos A=\cos 42^{\circ}=\frac{\text{adjacent side to A}}{\text{hypotenuse}}=\frac{270}{c}$
$\implies c=\frac{270}{\cos 42^{\circ}}=360$
