Answer
$\color{blue}{\sec{17^o}} = \csc{73^o}$
Work Step by Step
RECALL:
$\sec{\theta} = \csc{(90^o-\theta)}$
Thus,
$\csc{73^o} =\sec{(90^o-73^o)} = \sec{17^o}$.
Therefore,
$\sec{17^o} = \csc{73^o}$
Trigonometry 7th Edition
by McKeague, Charles P.; Turner, Mark D.
Published by
Cengage Learning
ISBN 10:
1111826854
ISBN 13:
978-1-11182-685-7
Chapters 1-3 - Cumulative Test - Page 176: 12
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