Answer
$706.9$ ft-lb
Work Step by Step
A package is pushed across a floor a distance of $52=S$ feet.
The force exerted on the package is $15=F$ pounds with an angle of $25^{\circ}=\theta$.
The work done is:
\[
F \cdot S \cos \theta=\text { Work done }
\]
Substitute $F . S$ and $\theta$
\[
\begin{array}{l}
52 \cdot 15 \cos 25^{\circ}=\text { Work done } \\
=780 \cdot 0.91 \\
=706.9 \mathrm{ft}-\mathrm{lb}
\end{array}
\]
The work done is $706.9$ ft-lb.
