Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 7 - Section 7.4 - The Area of a Triangle - 7.4 Problem Set - Page 396: 12

Answer

$= 52.0$ cm$^{2}$

Work Step by Step

$A = \frac{1}{2}absin(C)$ $= (0.5)(10)(12)sin(120)$ $= (0.5)120sin(120)$ $=(0.5)(103.92304...)$ $= 51.9615....$ cm$^{2}$ $= 52.0$ cm$^{2}$
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