Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 7 - Section 7.3 - The Ambiguous Case - 7.3 Problem Set - Page 390: 22

Answer

$B = 75.96^\circ \hspace{10pt} C =39.04^\circ \hspace{10pt} c =4.934 \,$ yd $B' =104.04^\circ \hspace{10pt} C'=10.96^\circ \hspace{10pt} c' =1.489 \,$ yd

Work Step by Step

$\sin{B} = \dfrac{7.6 \times \sin{65^\circ}}{7.1} = 0.9701$ $B = 75.96^\circ \hspace{40pt} B' =180-B= 104.04^\circ $ $C = 180-(A+B) = 39.04^\circ$ $c = \dfrac{7.1 \times \sin{39.04^\circ}}{\sin{65}} = 4.934 \, yd$ $C'= 180-(A+B') = 10.96^\circ$ $c' = \dfrac{7.1 \times \sin{10.96^\circ}}{\sin{65}} = 1.489 \,yd$
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