Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 7 - Section 7.3 - The Ambiguous Case - 7.3 Problem Set - Page 390: 15

Answer

$B = 34.89^\circ \hspace{10pt} A =117.277^\circ \hspace{10pt} a = 660.56 \,m$ $B' = 145.11^\circ \hspace{10pt} A' = 7.057^\circ \hspace{10pt} a' = 91.308 \, m$

Work Step by Step

$\sin{B} = \dfrac{b \sin{C}}{c} = \dfrac{425 \sin{(27.833^\circ)}}{347}$ $\sin{B} = 0.572$ $B = 34.89^\circ\hspace{40pt} B' = 145.11^\circ$ $A = 180-(B+C) = 117.277^\circ$ $a = \dfrac{c \sin{A}}{\sin{C}} = \dfrac{347 \times \sin{117.277}}{\sin{27.833}}$ $a = 660.56 \,m$ $B' + C < 180 \hspace{10pt} \therefore B'$ is valid. $A' = 180-(B+C') = 7.057^\circ$ $a' = \dfrac{c \sin{A'}}{\sin{C}} = \dfrac{347 \times \sin{7.057}}{\sin{27.833}}$ $a' = 91.308 \, m$
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