Answer
$c\approx98.5\, cm$
Work Step by Step
$A=43^{\circ}, B=12^{\circ},b=25\, cms.$
So, $C=180^{\circ}-(A+B)=180^{\circ}-(43^{\circ}+12^{\circ})=180^{\circ}-55^{\circ}=125^{\circ}$
Using laws of sines,
$\frac{sinB}{b}=\frac{sinC}{c}$
$\frac{\sin12^{\circ}}{25}=\frac{\sin125^{\circ}}{c}$
$c=\frac{sin125^{\circ}}{sin12^{\circ}}\times25\,cms$
so, $c\approx98.5\, cms$
