Answer
$\theta=90^{\circ}or \,270^{\circ}$
Work Step by Step
$\sin\theta\cos\theta-2\cos\theta=0$
$\cos \theta(\sin\theta-2)=0$
So, either $\cos\theta=0\,or\,\sin\theta=2$
When, $\cos\theta=0,$
$\theta=90^{\circ},270^{\circ}$
Now, $\sin\theta=2$ is not possible, since $|\sin\theta|\leq1$
For, $0^{\circ}\leq\,x\lt360^{\circ}$
So, $\theta=90^{\circ}or \,270^{\circ}$
