Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 7 - Section 7.1 - The Law of Sines - 7.1 Problem Set - Page 368: 24

Answer

$sinB=0.678$ Possible values of B are $B_{1}=42.7^{\circ}$ & $B_{2}=137.3^{\circ}$

Work Step by Step

$A=40^{\circ},b=19ft,a=18ft$ Using laws of sines, $\frac{sinA}{a}=\frac{sinB}{b}$ $\frac{sin40^{\circ}}{18}=\frac{sinB}{19}$ so,$sinB=0.678$ There are 2 possible values of B, so $B_{1}=42.7^{\circ}$ & $B_{2}=180^{\circ}-42.7^{\circ}=137.3^{\circ}$ so $B_{1}=42.7^{\circ}$ & $B_{2}=137.3^{\circ}$
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