Answer
$2\sin6x\cos2x$
Work Step by Step
We know that $\sin A+\sin B=2\sin\frac{A+B}{2}\cos\frac{A-B}{2}$, hence $\sin 8x+\sin 4x=2\sin6x\cos2x$
Trigonometry 7th Edition
by McKeague, Charles P.; Turner, Mark D.
Published by
Cengage Learning
ISBN 10:
1111826854
ISBN 13:
978-1-11182-685-7
Chapter 6 - Section 6.4 - Parametric Equations and Further Graphing - 6.4 Problem Set - Page 353: 52
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