Answer
$x^2/9-y^2/9=1$.
Work Step by Step
We know that $\tan^2 A+1=\sec^2 A$.
Hence here $(y/3)^2+1=(x/3)^2$, thus $x^2/9-y^2/9=1$.
Trigonometry 7th Edition
by McKeague, Charles P.; Turner, Mark D.
Published by
Cengage Learning
ISBN 10:
1111826854
ISBN 13:
978-1-11182-685-7
Chapter 6 - Section 6.4 - Parametric Equations and Further Graphing - 6.4 Problem Set - Page 352: 31
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