Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 6 - Section 6.1 - Solving Trigonometric Equations - 6.1 Problem Set - Page 326: 26

Answer

a) $= (2x + 1)(x+1)$ b) $= (2sin\theta + 1)(sin\theta + 1)$

Work Step by Step

a) $2x^{2} +3x + 1$ $= 2x^{2} + 2x + 1x + 1$ $= 2x(x + 1) + 1(x+1)$ $= (2x + 1)(x+1)$. b) $2(sin\theta)^{2} + 3sin\theta + 1$ Let $sin\theta = x$ to get $2x^{2} + 3x + 1$ (Exact same equation as in Section a) $= (2x+1)(x+1)$ Replace $x = sin\theta$ to get $(2sin\theta + 1)(sin\theta + 1)$.
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