Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 5 - Section 5.5 - Additional Identities - 5.5 Problem Set - Page 312: 43

Answer

See the steps.

Work Step by Step

$\sin{3x} + \sin{x} = 2 \sin{2x} \cos{x} $ $\cos{3x} - \cos{x} = -2 \sin{2x} \sin{x}$ $RHS = \dfrac{2 \sin{2x} \cos{x} }{-2 \sin{2x} \sin{x}} = -\cot{x} = LHS$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.