Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 5 - Section 5.4 - Half-Angle Formulas - 5.4 Problem Set - Page 305: 54

Answer

See the steps.

Work Step by Step

$RHS =\dfrac{\sin^2{\theta}}{1+\cos{\theta}} = \dfrac{1-\cos^2{\theta}}{1+\cos{\theta}}$ $RHS = \dfrac{(1-\cos{\theta})(1+\cos{\theta})}{1+\cos{\theta}} = 1-\cos{\theta} = 2 \sin^2{\dfrac{\theta}{2}} = LHS$
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