Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 5 - Section 5.4 - Half-Angle Formulas - 5.4 Problem Set - Page 305: 51

Answer

See the steps.

Work Step by Step

$LHS =\tan{\dfrac{x}{2}}+\cot{\dfrac{x}{2}}= \dfrac{\sin{x}}{1+\cos{x}} +\dfrac{1+\cos{x}}{\sin{x}}$ $LHS = \dfrac{\sin^2{x}+1+2\cos{x}+\cos^2{x}}{(1+\cos{x})(\sin{x})} = \dfrac{2+2\cos{x}}{(1+\cos{x})(\sin{x})}$ $LHS = \dfrac{2(1+\cos{x})}{(1+\cos{x})(\sin{x})}= \dfrac{2}{\sin{x}} = 2 \csc{x} = RHS$
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