Answer
See the steps.
Work Step by Step
$RHS = \csc{B} - \cot{B} = \dfrac{1}{\sin{B}}- \dfrac{\cos{B}}{\sin{B}}= \dfrac{1-\cos{B}}{\sin{B}}$
$RHS = \tan{\dfrac{B}{2}} = LHS$
Trigonometry 7th Edition
by McKeague, Charles P.; Turner, Mark D.
Published by
Cengage Learning
ISBN 10:
1111826854
ISBN 13:
978-1-11182-685-7
Chapter 5 - Section 5.4 - Half-Angle Formulas - 5.4 Problem Set - Page 305: 49
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