Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 5 - Section 5.4 - Half-Angle Formulas - 5.4 Problem Set - Page 304: 3

Answer

$\pm \sqrt{\dfrac{1-\cos{x}}{2}}$

Work Step by Step

Using the double angle formula: $$\cos{2A} = 1 - 2 \sin^2{A}$$ $$2 \sin^2{A}= 1-\cos{2A}$$ $$\sin^2{A} = \dfrac{1-\cos{2A}}{2}$$ $$\therefore \sin{A} = \pm \sqrt{\dfrac{1-\cos{2A}}{2}}$$ Replacing $A$ with $\dfrac{x}{2}$: $\sin{\dfrac{x}{2}} = \pm \sqrt{\dfrac{1-\cos{x}}{2}}$
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