Answer
See the steps.
Work Step by Step
$RHS = \cot{x}-\tan{x} = \dfrac{\cos{x}}{\sin{x}} - \dfrac{\sin{x}}{\cos{x}} = \dfrac{\cos^2{x}-\sin^2{x}}{\sin{x}\cos{x}}$
$RHS =\dfrac{\cos{2x}}{0.5 \sin{2x}} = 2 \cot{2x} = LHS$
Trigonometry 7th Edition
by McKeague, Charles P.; Turner, Mark D.
Published by
Cengage Learning
ISBN 10:
1111826854
ISBN 13:
978-1-11182-685-7
Chapter 5 - Section 5.3 - Double-Angle Formulas - 5.3 Problem Set - Page 297: 50
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