Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 5 - Section 5.3 - Double-Angle Formulas - 5.3 Problem Set - Page 297: 47

Answer

See the steps.

Work Step by Step

$RHS = \dfrac{\sin{2\theta}}{1- \cos{2\theta}} = \dfrac{2 \sin{\theta} \cos{\theta}}{1- \cos^2 {\theta} + \sin^2 {\theta}} $ $RHS = \dfrac{2 \sin{\theta} \cos{\theta}}{\sin^2{\theta} + \sin^2 {\theta}} = \dfrac{2 \sin{\theta} \cos{\theta}}{2 \sin^2 {\theta}}$ $RHS = \dfrac{\cos{\theta}}{\sin{\theta}} = \cot{\theta} = LHS$
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