Answer
$\dfrac{24}{7}$
Work Step by Step
$\tan{2A} = \dfrac{2 \tan{A}}{1- \tan^2 {A}}$
$\tan{2A} = \dfrac{2 \times \dfrac{3}{4}}{1-(\dfrac{3}{4})^2}$
$\tan{2A} = \dfrac{24}{7}$
Trigonometry 7th Edition
by McKeague, Charles P.; Turner, Mark D.
Published by
Cengage Learning
ISBN 10:
1111826854
ISBN 13:
978-1-11182-685-7
Chapter 5 - Section 5.3 - Double-Angle Formulas - 5.3 Problem Set - Page 297: 34
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