Answer
See the steps.
Work Step by Step
$LHS =\dfrac{\sin{(A-B)}}{\cos{A} \cos{B}} = \dfrac{\sin{A} \cos{B} -\sin{B} \cos{A}}{\cos{A} \cos{B}}$
$LHS = \dfrac{\sin{A}}{\cos{A}} - \dfrac{\sin{B}}{\cos{B}}$
$LHS = \tan{A} - \tan{B} = RHS$
Trigonometry 7th Edition
by McKeague, Charles P.; Turner, Mark D.
Published by
Cengage Learning
ISBN 10:
1111826854
ISBN 13:
978-1-11182-685-7
Chapter 5 - Section 5.2 - Sum and Difference Formulas - 5.2 Problem Set - Page 290: 63
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