Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 5 - Section 5.2 - Sum and Difference Formulas - 5.2 Problem Set - Page 288: 14

Answer

$\frac{\sqrt 3 +1}{2\sqrt 2}$

Work Step by Step

$\sin\frac{7π}{12}$= $\sin(\frac{π}{3}+\frac{π}{4})$ =$\sin\frac{π}{3}\cos\frac{π}{4}+\cos\frac{π}{3}\sin\frac{π}{4}$ =$\frac{\sqrt 3}{2}×\frac{1}{\sqrt 2}+\frac{1}{2}×\frac{1}{\sqrt 2}$ = $\frac{\sqrt 3 +1}{2\sqrt 2}$
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