Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 4 - Section 4.4 - The Other Trigonometric Functions - 4.4 Problem Set - Page 227: 24

Answer

$Period = 4\pi $ See below

Work Step by Step

If B > 0, then the graphs of $y = \sec(Bx)$ and $y = \csc(Bx)$ will have $Period = \frac{2\pi}{B}$ For equation $y = 3 \csc \frac{1}{2}x$ $Period = \frac{2\pi}{\frac{1}{2}} = 4\pi $
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