Answer
see below
Work Step by Step
$ y = \csc (4x)$
We begin with graph of $y = \sin (4x)$
Amplitude = 1,
For one cycle
$0 \leq 4x \leq 2\pi$
$0 \leq x \leq \frac{\pi}{2}$
So period is $\frac{\pi}{2}$
Now
To sketch the graph of the cosecant function, we note that the zeros of the sine
graph correspond to the vertical asymptotes of the cosecant graph, and the peaks and
valleys of the sine graph correspond to the valleys and peaks of the cosecant graph,
respectively
the range of the function is $y \geq 1$ or $y \leq -1$
Using graph of $y = \sin (4x)$ as aid we can draw graph of y = \csc (4x)$