Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 4 - Section 4.4 - The Other Trigonometric Functions - 4.4 Problem Set - Page 227: 13

Answer

see below

Work Step by Step

$ y = \csc (3x)$ We begin with graph of $y = \sin (3x)$ Amplitude = 1, For one cycle $0 \leq 3x \leq 2\pi$ $0 \leq x \leq \frac{2\pi}{3}$ So period is $\frac{2\pi}{3}$ Now To sketch the graph of the cosecant function, we note that the zeros of the sine graph correspond to the vertical asymptotes of the cosecant graph, and the peaks and valleys of the sine graph correspond to the valleys and peaks of the cosecant graph, respectively the range of the function is $y \geq 1$ or $y \leq -1$ Using graph of $y = \sin (3x)$ as aid we can draw graph of y = \csc (3x)$
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