Answer
$Amplitude = 2$
$Period = 4\pi$
$Horizontal\ shift = \pi $ (right shift $\pi$)
$Vertical\ shift = 3$ (3 units shift upward)
$Phase = -\frac{\pi}{2}$
Work Step by Step
If C is any real number and $B> 0$, then the graphs of $y = k + A\sin(Bx+C)$ and $y = k + A\cos (Bx+C)$ will have
$Amplitude = |A|$
$Period = \frac{2\pi}{B}$
$Horizontal\ shift = –\frac{C}{B}$
$Vertical\ shift = k$
$Phase = C$
so for $y = 3 + 2\sin (\frac{1}{2}x - \frac{\pi}{2})$
$Amplitude = |2| = 2$
$Period = \frac{2\pi}{\frac{1}{2}} = 4\pi$
$Horizontal\ shift = (–\frac{-\frac{\pi}{2}}{\frac{1}{2}}) = \pi $ (right shift)
$Vertical\ shift = 3$ (3 units shift upward)
$Phase = -\frac{\pi}{2}$