Answer
Graph of $y = 1 + \sin (2x - \pi )$ will be
Graph of $y = \sin (2x - \pi )$ (problem 41) shifted 1 unit vertically
Work Step by Step
We know that,
The graphs of $y = k + \sin x$ and $y = k + \cos x$ will be sine and cosine graphs that have been translated vertically k units upward if $k > 0$, or k units downward if $k < 0$,
Using this
Graph of $y = 1 + \sin (2x - \pi )$ will be
Graph of $y = \sin (2x - \pi )$ (problem 41) shifted 1 unit vertically
