Answer
$\frac{\sqrt3}{2}$
Work Step by Step
Plugging in $x=\frac{\pi}{2},y=\frac{\pi}{6}$ we get: $\sin(\frac{\pi}{2}+\frac{\pi}{6})=\sin\frac{2\pi}{3}=\frac{\sqrt3}{2}$
Trigonometry 7th Edition
by McKeague, Charles P.; Turner, Mark D.
Published by
Cengage Learning
ISBN 10:
1111826854
ISBN 13:
978-1-11182-685-7
Chapter 4 - Section 4.2 - Amplitude, Reflection, and Period - 4.2 Problem Set - Page 207: 73
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