Answer
$\approx87.46$
Work Step by Step
$|V_x|=|V|\cos\theta,|V_y|=|V|\sin\theta$
Thus $|V|=\sqrt{|V_x|^2+|V_y|^2}=\sqrt{45^2+75^2}\approx87.46$
Trigonometry 7th Edition
by McKeague, Charles P.; Turner, Mark D.
Published by
Cengage Learning
ISBN 10:
1111826854
ISBN 13:
978-1-11182-685-7
Chapter 3 - Section 3.5 - Velocities - 3.5 Problem Set - Page 169: 70
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