Answer
41.888 radians/hr
Work Step by Step
If $P$ is a point moving with uniform circular motion on a circle of radius $r$, and the line from the center of the circle through $P$ sweeps out a central angle $\theta$ in an amount of time $t$, then the angular velocity, $\omega$ (omega), of $P$ is calculated as $\omega=\frac{\theta}{t}$.
We are given that $\theta=24\pi$ radians and $t=1.8$ hr.
Therefore, $\omega=\frac{24\pi radians}{1.8 hr}\approx41.888$ radians/hr.