Answer
.175 mi
Work Step by Step
We know that if point $P$ is a point on a circle of radius $r$, and $P$ moves in a distance $s$ on the circumference of the circle in an amount of time $t$, then the linear velocity, $v$, of $P$ is calculated as $v=\frac{s}{t}$.
As a result, we also know that $s=vt$.
We are given that $v=63$ mi/hr and $t=10 sec(=\frac{1}{360} hr)$.
Therefore, $s=(63 mi/hr)(\frac{1}{360} hr)=\frac{63mi/hr}{360hr}=\frac{63mi/hr\div9}{360hr\div9}=\frac{7mi/hr}{40hr}=.175$ mi.
