Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 3 - Section 3.4 - Arc Length and Area of a Sector - 3.4 Problem Set - Page 153: 17

Answer

the shuttle travels $1400\pi\,miles$ (exact value) or $4.40\times10^{3}\,miles$ (approximate value)

Work Step by Step

Radius $r=(4000+200)\,miles=4200\,miles$ Inorder to complete $360^{\circ}$ the space shuttle needs 6 hours. Therefore in 1 hour it covers an angle of $360^{\circ}\times\frac{1}{6}=60^{\circ}$. That is, central angle $\theta=(60\times\frac{\pi}{180})\,radians=\frac{\pi}{3}\,rad$ Arc length $s=r\times\theta=4200\,miles\times\frac{\pi}{3}=1400\pi\,miles=4400\,miles$
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