Answer
$\frac{14}{3}$
Work Step by Step
$4-\frac{2}{3}\sin (3\times\frac{\pi}{6}-\pi)=4-\frac{2}{3}\sin (-\frac{\pi}{2})$
$=4-(\frac{2}{3}\times-\sin \frac{\pi}{2})=4-(\frac{2}{3}\times-1)=4+\frac{2}{3}=\frac{14}{3}$
Trigonometry 7th Edition
by McKeague, Charles P.; Turner, Mark D.
Published by
Cengage Learning
ISBN 10:
1111826854
ISBN 13:
978-1-11182-685-7
Chapter 3 - Section 3.2 - Radians and Degrees - 3.2 Problem Set - Page 133: 79
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