Answer
$-\frac{1}{2}$
Work Step by Step
$\sin(\frac{\pi}{6}-\frac{\pi}{3})$ = $\sin(\frac{-3\pi}{18}) = \sin(-\frac{\pi}{6})$
Using the identity $\sin(-x) = -\sin x$
we obtain, $\sin(-\frac{\pi}{6})$ = $-\sin\frac{\pi}{6}$ = $-\frac{1}{2}$
Trigonometry 7th Edition
by McKeague, Charles P.; Turner, Mark D.
Published by
Cengage Learning
ISBN 10:
1111826854
ISBN 13:
978-1-11182-685-7
Chapter 3 - Section 3.2 - Radians and Degrees - 3.2 Problem Set - Page 133: 76
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