Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 3 - Section 3.1 - Reference Angle - 3.1 Problem Set - Page 123: 90

Answer

$ \frac{3\sqrt 2}{4} $ or Approximately 1.06 unit

Work Step by Step

Given that each of the shorter sides is $ \frac{3}{4}$ In a 45°–45°–90° triangle, if each of the shorter side is 'x'. then as per Pythagorean theorem- $Hypotenuse^{2}$ = $x^{2} + x^{2}$ = 2$x^{2}$ Therefore hypotenuse = $x\sqrt 2$ Therefore hypotenuse of given triangle = $ \frac{3}{4} \times \sqrt 2$ = $ \frac{3\sqrt 2}{4} $ $Hypotenuse \approx \frac{3}{4} \times 1.414$ $Hypotenuse \approx 1.06$
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