Answer
reference angle = $36.6^o$
Refer to the image below for the drawing.
Work Step by Step
The angle is positive so from the positive x-axis, move $143.4$ degrees counterclockwise.
(refer to the attached image in the answer part above)
The terminal side of the angle is in Quadrant II.
The reference angle of an angle $\theta$ in Quadrant II can be found using the formula $180^o-\theta$
Thus, the reference angle of the given angle is:
$=180^o - 143.4^o
\\=36.6^o$
