Answer
$126.4^{\circ}$
Work Step by Step
Given-
$\cot\theta$ = - $0.7366$ , $\theta$ belongs to Q II
We will find reference angle of $\theta$ first, using calculator in degree mode by the$\frac{1}{x}$ and $\tan^{-1}$ key with the positive value $0.7366$ as $\tan\theta$ = $\frac{1}{\cot\theta}$
$0.7366$ → $\frac{1}{x}$ → $\tan^{-1}$→→ 53.624639621
i.e. reference angle of $\theta$ = $53.624639621^{\circ}$
The desired angle $\theta$ is in Q II, whose reference angle is $53.624639621^{\circ}$.
Also $0^{\circ}\leq \theta\lt 360^{\circ}$
Therefore-
$\theta$ = $180^{\circ} - 53.624639621^{\circ}$
= $126.37536038^{\circ}$
= $126.4^{\circ}$
(to the nearest tenth of a degree)