Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 3 - Section 3.1 - Reference Angle - 3.1 Problem Set - Page 122: 58

Answer

$30.5^{\circ}$

Work Step by Step

Given- $\tan\theta$ = $0.5890$ , $\theta$ belongs to Q I and $0^{\circ}\leq \theta\lt 360^{\circ}$ We will find reference angle of $\theta$ first, using calculator in degree mode by the $\tan^{-1}$ key with the value $0.5890$- $0.5890$ → $\tan^{-1}$→→ 30.498085114 i.e. reference angle of $\theta$ = $30.5^{\circ}$ (to the nearest tenth of a degree) The desired angle $\theta$ is in Q I, whose reference angle is $30.5^{\circ}$. Therefore- $\theta$ = $30.5^{\circ}$ ( for QI ref. angle of $\theta$ = $\theta$ as $0^{\circ}\leq \theta\lt 360^{\circ}$ )
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