Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 3 - Section 3.1 - Reference Angle - 3.1 Problem Set - Page 122: 50

Answer

$\sec 314^{\circ} 40'$ = 1.4225

Work Step by Step

Given function- $\sec 314^{\circ} 40'$ We have to convert it to decimal degrees first- $\sec 314^{\circ} 20'$= $\sec (314^{\circ} + 40')$ = $\sec (314^{\circ} + (\frac{40}{60})^{\circ})$ = $\sec (314^{\circ} + (0.6667)^{\circ})$ = $\sec 314.6667^{\circ} $ Using calculator in degree mode- 314.6667 → $\cos$ → $\frac{1}{x}$ (Recall $\sec\theta$ = $\frac{1}{\cos\theta}$) $\sec 314.6667^{\circ}$ = 1.4225125995 Rounding it to four places past the decimal point- $\sec 314.6667^{\circ}$ = 1.4225 or $\sec 314^{\circ} 40'$ = 1.4225
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