Answer
$\sin{14^o} =\cos{76^o}$
Work Step by Step
RECALL:
$\sin{\theta} = \cos{(90^o-\theta)}$.
Thus,
$\sin{14^o} = \cos{(90^o-14^o)}=\cos{76^o}$
Trigonometry 7th Edition
by McKeague, Charles P.; Turner, Mark D.
Published by
Cengage Learning
ISBN 10:
1111826854
ISBN 13:
978-1-11182-685-7
Chapter 2 - Test - Page 111: 5
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