Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 2 - Section 2.5 - Vectors: A Geometric Approach - 2.5 Problem Set - Page 109: 58

Answer

c) $|\textbf{V}|=9.9$, $\theta=13^{\circ}$

Work Step by Step

$|\textbf{V}|=\sqrt {|\textbf{V}_{x}|^{2}+|\textbf{V}_{y}|^{2}}=\sqrt {(9.6)^{2}+(2.3)^{2}}=9.9$ $\theta=\tan^{-1}(\frac{|\textbf{V}_{y}|}{|\textbf{V}_{x}|})=\tan^{-1}(\frac{2.3}{9.6})=13^{\circ}$
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